求骨架矩阵注意的两个问题!
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第一个问题!求骨架矩阵过程中:必须要先缩点处理,也就是一定要把原始矩阵转换成一个DAG图
第二个问题!缩点运算,尽量不要用原序!得到的缩减矩阵不要保留原序!
DAG图求骨架矩阵的代数公式:S=R-(R-I)2-I 如果非DAG图用此公式,得到的不是骨架矩阵!
显示的是一个随机 12 * 12 的方阵
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第一种情况:未缩减的条件下使用骨架矩阵的代数公式计算,计算的结果如下
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一般性骨架矩阵如下!
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得到的不是骨架矩阵!
第二种情况:使用原序法得到缩减矩阵,再求骨架矩阵,计算的结果如下
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子+辰 | 丑 | 寅 | 卯 | 巳 | 午 | 未 | 申 | 酉 | 戌 | 亥 |
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第三种情况:新序法求缩减矩阵,再求骨架矩阵,计算的结果如下
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子+辰 | 丑 | 申 | 寅 | 卯 | 未 | 巳 | 午 | 酉 | 亥 | 戌 |
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比较两者的箭头方向后者的箭头为同一方向!
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