求骨架矩阵注意的两个问题！
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第一个问题！求骨架矩阵过程中：必须要先缩点处理，也就是一定要把原始矩阵转换成一个DAG图
第二个问题！缩点运算，尽量不要用原序！得到的缩减矩阵不要保留原序！
DAG图求骨架矩阵的代数公式：S=R-(R-I)2-I 如果非DAG图用此公式，得到的不是骨架矩阵！
显示的是一个随机 12 * 12 的方阵
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第一种情况：未缩减的条件下使用骨架矩阵的代数公式计算，计算的结果如下
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一般性骨架矩阵如下！
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原始矩阵是一个无回路矩阵，得到的是骨架矩阵！
第二种情况：使用原序法得到缩减矩阵，再求骨架矩阵，计算的结果如下
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子 | 丑 | 寅 | 卯 | 辰 | 巳 | 午 | 未 | 申 | 酉 | 戌 | 亥 |
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第三种情况：新序法求缩减矩阵，再求骨架矩阵，计算的结果如下
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比较两者的箭头方向后者的箭头为同一方向！
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